b= (3x-2)(2x+3)-(3x-2) au carre c= (4x+7)au carre - 4 developper et reduire b et c factoriser b et c calculer b pour x = -

1)devolopper:
B= (3x-2)(2x+3)-(3x-2)²=(6x²+9x-4x-6)-(9x²-12x+4)
=(6x²+5x-6)-(9x²-12x+4)
=6x²+5x-6-9x²+12x-4
=3x²+17x-10
c= (4x+7)²-4=16x²+56x+49-4
=16+56x+45
2)factoriser:
B= (3x-2)(2x+3)-(3x-2)²=(3x-2)(2x+3)-(3x-2)(3x-2)
=(3x-2)[(2x+3)-(3x-2)]
=(3x-2)(2x+3-3x+2)=(3x-2)(5-x)
C=(4x+7)²-4=(4x+7)²-2²
=((4x+7)-2)((4x+7)+2)
=(4x+7-2)(4x+7+2)=(4x+5)(4x+9)
calculer b
 B= (3x-2)(2x+3)-(3x-2)²=3x²+17x-10=3(-2/3)²+17(-2/3)-10
=3(4/9)+(-34/3)-10
=(12/9)-(34/3)-10
=(12/9)-(102/9)-(90/9)
=(-180/90)= -2