Mathématiques

Question

bonjour pouvez vous m'aider.
a.4/3-(1/2+7/8)
b.4/3-7/5-(3/5-5/7)

merci d'avance!​

1 Réponse

  • Bonjour


    a.4/3-(1/2+7/8)

    = 4/3 - [(1 x 4)/(2 x 4) + 7/8]
    = 4/3 - (4/8 + 7/8)

    = 4/3 - 11/8

    = (4 x 8)/(3 x 8) - (11 x 3)/(8 x 3)

    = 32/24 - 33/24

    = -1/24

    b.4/3-7/5-(3/5-5/7) 

    = 4/3 - 7/5 - 3/5 + 5/7

    = 4/3 - 7/5 - (3 x 7)/(5 x 7) + (5 x 5)/(7 x 5)

    = 4/3 - 7/5 - 21/35 + 25/35

    = 4/3 - (7 x 7)/(5 x 7) + 4/35

    = 4/3 - 49/35 + 4/35

    = 4/3 - 45/35

    = 4/3 - (9 x 5)/(7 x 5)

    = 4/3 - 9/7

    = (4 x 7)/(3 x 7) - (9 x 3)/(7 x 3)

    = 28/21 - 27/21

    = 1/21

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